30 Mei 2011

Program Java : Program Wartel Sederhana

30 Mei 2011
kemaren sempet searching-searching ga jelas, dapet program wartel sederhana., Semoga bisa membantu. Tapi berhubung saya lupa dimana nie dapat programnya,mohon maaf jadi ga bisa mencantumkan link sumbernya. Tapi kalau saya ingat, pasti saya lampirkan link sumbernya ^^v

coding:
import java.io.*;

public class Wartel
{
public int input()
{
String d;
int c=0;
BufferedReader i = new BufferedReader(new InputStreamReader(System.in));
try
{
d = i.readLine();
c= Integer.parseInt(d);
}
catch(IOException exe)
{
System.out.print("salah input");
}
return c;
}

public static void main(String [] args)
{

int h,m,s,h1,m1,s1,W,P,B,Jum1,Jum2;

Wartel z = new Wartel();
System.out.println("=================================================");
System.out.println("PERUSAHAAN TELEPON");

System.out.print("JAM MULAI BICARA:\n\n");
System.out.print("Jam : ");
h=z.input();
System.out.print("Menit : ");
m=z.input();
System.out.print("Detik : ");
s=z.input();

System.out.println();
System.out.print("JAM SELESAI BICARA:\n\n");
System.out.print("Jam : ");
h1=z.input();
System.out.print("Menit : ");
m1=z.input();
System.out.print("Detik : ");
s1=z.input();

if((h<=23) && (m<=59) &&( s<=59) && (h1<=23) && (m1<=59) &&( s1<=59))
{
Jum1=((h*3600)+(m*60)+s);
Jum2=((h1*3600)+(m1*60)+s1);
if (Jum1>Jum2)
{
System.out.println("Inputan salah, Jam Selesai Lebih Besar daripada Jam Mulai");
}
else
{
W=Jum2-Jum1;

P=W/60;

if (W % 60 != 0)
{
P=P+1;
}

System.out.println("\nJUMLAH PULSA : "+P);

B=P*100;

System.out.println("\nTOTAL BIAYA YANG HARUS DI BAYAR :Rp."+B);

System.out.println("=================================================");
}
}
else
System.out.print("Inputan salah");
}

}


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